dqwh1201 2012-04-25 23:07
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Search.php无效,无法显示任何结果

I'm trying to figue out how to make my search.php script work with mySQL. I can't get the information to show up. Not sure where the problem is.

PAGE 1:

<form action="search_result.php" method="GET">
    <input type="text" name="reg" />
    <input type="submit" value="Search" />
</form>

PAGE 2:

<?php
$host="localhost";
$username="XXXXXXXXXXX";
$password="XXXXXXXXXXX";
$db_name="XXXXXXXXXXXX";
$tbl_name="reg_add";
mysql_connect("$host", "$username", "$password") or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");


$record = $_POST['record']; // if coming from e.g. a form
$result=mysql_query(" SELECT * FROM reg_add WHERE reg='" . mysql_real_escape_string($record) . "'");


$row = mysql_fetch_assoc($result);
$first_name = $row['first_name'];
$last_name = $row['last_name'];
$reg = $row['reg'];
?>

<input  name="reg" value="<? echo "$record" ?>">

<input  name="first_name" value="<? echo "$first_name" ?>">

<input  name="last_name" value="<? echo "$last_name" ?>">
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3条回答 默认 最新

  • dsfw2154 2012-04-26 08:30
    关注

    You form is method GET and in your PHP you use this:

    $record = $_POST['record']; // if coming from e.g. a form
    

    How are you gonna get the POST['record'] if your form has the method GET?

    I guess you should or change your form to:

    method="POST" 
    

    or change your $record in php to:

    $record = $_GET['record'];
    

    Try this version:

    You form:

        <form action="search_result.php" method="POST">
        <input type="text" name="reg" id="reg" />
        <input type="submit" name="Submit" id="Submit" value="Search" />
    </form>
    

    search_result.php :

    <?php
    
    $host       ="localhost";
    $username   ="XXXXXXXXXXX";
    $password   ="XXXXXXXXXXX";
    $db_name    ="XXXXXXXXXXXX";
    $tbl_name   ="reg_add";
    
    /* Connect to MySQL database */
    mysql_connect("$host", "$username", "$password") or die("Error connecting to database");
    mysql_select_db("$db_name")or die("Error selecting database");
    
    $error = '';
    
    if (isset($_POST['Submit'])) {
    
    
        if (!empty($_POST['reg'])) {
    
            $record = $_POST['reg']; // if coming from e.g. a form
    
            $query = mysql_query("SELECT * FROM reg_add WHERE reg='" . mysql_real_escape_string($record) . "'");
            $result = mysql_num_rows($query);
    
            if ($result != 0) {
    
                $row = mysql_fetch_array($query);
    
                $first_name = $row['first_name'];
                $last_name = $row['last_name'];
                $reg = $row['reg'];
    
            } else {
    
                $error = 'No result have been found!';
    
            }
    
        } else {
    
            $error = 'You have not entered the search field, <a href="javascript:history.back(1)">Go back</a>.';
    
        }
    }
    
    if (!empty($error)) { echo $error; } 
    ?>
    
    
    <input  name="reg" value="<? echo $record; ?>">
    
    <input  name="first_name" value="<? echo $first_name; ?>">
    
    <input  name="last_name" value="<? echo $last_name; ?>">
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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