PHP如何根据查询字符串值显示隐藏DIVS

Question

Essentially, I'm completely new at PHP - using dreamweaver cs6 (its all i have)

I have to get the value of a query string (someurl.com/id=something). After i get the value, I need to show a single div based on the ID.

While I know there really isn't any REAL "page load" event for PHP, I'd like to have it when the page opens.

So, how do I accomplish this?

I started with this:

<?php
    $stringId = $_GET['id']
   ?>

    <script language="javascript">      
        document.getElementById('$stringId').style.display = "block";
    </script>
    <?
?>

Since I don't have a server setup, will something like this work? Would you suggest something else? Am I completely wrong?

Any input would be appreciated. Thank you.

Answer 1

You should set the style inline with out relying on javascript as some users may have javascript turned off.

<div <?php if($_GET['id'] == 'X'){ ?>style="display: block;"<?php } ?>>
    your div content
</div>

with an else as requested

<div style="<?php if($_GET['id'] == 'X'){ ?>display: block;<?php } else { ?>display: none;<?php } ?">
    your div content
</div>

you could also use a predefined css class

based on your comment about having way to many to do a switch if you need to mix it up just insert this

<script language="javascript">      
    document.getElementById('<?php echo $_GET['id']; ?>').style.display = "block";
</script>