需要以某种不同方式在索引为零的数组

Question

$i=0;
foreach($tagss as $tagdetails)
    {
        if($i==0)
 $tags_array[]["00"]=array("id"=>$i,"name"=>"all","type"=>"gift_finder","parent_id"=>null,"url"=>"all","readonly"=>"0","deleted"=>"0");


 $tags_array[][$tagdetails->id]=array("id"=>$tagdetails->id,"name"=>$tagdetails->title,"type"=>"gift_finder","parent_id"=>null,"url"=>$tagdetails->title,"readonly"=>"0","deleted"=>"0");


    $i++;
    }
echo json_encode($tags_array);

my out put of above code is :-

[{"00":{"id":0,"name":"all","type":"gift_finder","parent_id":null,"url":"all","readonly":"0","deleted":"0"}},{"1":{"id":"1","name":"Adventure","type":"gift_finder","parent_id":null,"url":"Adventure","readonly":"0","deleted":"0"}},{"2":{"id":"2","name":"cool","type":"gift_finder","parent_id":null,"url":"cool","readonly":"0","deleted":"0"}}] 

that is the right but i want the out put like (just need 0 instead of 00) so i tried :-

   $i=0;
foreach($tagss as $tagdetails)
    {
        if($i==0)
 $tags_array[]["0"]=array("id"=>$i,"name"=>"all","type"=>"gift_finder","parent_id"=>null,"url"=>"all","readonly"=>"0","deleted"=>"0");


 $tags_array[][$tagdetails->id]=array("id"=>$tagdetails->id,"name"=>$tagdetails->title,"type"=>"gift_finder","parent_id"=>null,"url"=>$tagdetails->title,"readonly"=>"0","deleted"=>"0");


    $i++;
    }
echo json_encode($tags_array);

ouput of the above code :-

[[{"id":0,"name":"all","type":"gift_finder","parent_id":null,"url":"all","readonly":"0","deleted":"0"}],{"1":{"id":"1","name":"Adventure","type":"gift_finder","parent_id":null,"url":"Adventure","readonly":"0","deleted":"0"}},{"2":{"id":"2","name":"cool","type":"gift_finder","parent_id":null,"url":"cool","readonly":"0","deleted":"0"}}] 

that is logically right that it is put the first element in the array and treat next element at first index but i need 0 index separately

Any suggestion please thanks in advance .

in summary I need

[{"0":{"id":0,"name":"all","type":"gift_finder","parent_id":null,"url":"all","readonly":"0",
"deleted":"0"}},
{"1":"id":"1","name":"Adventure","type":"gift_finder","parent_id":null,"url":"Adventure","readonly":"0","deleted":"0"}},
{"2":"id":"2","name":"cool","type":"gift_finder","parent_id":null,"url":"cool","readonly":"0","deleted":"0"}
}] 

Answer 1

You just need to pass option to your json_encode() call. It is JSON_FORCE_OBJECT:

echo json_encode($tags_array, JSON_FORCE_OBJECT);

then you'll able to result in an object for numeric keys (so you don't need to pass keys from PHP at all). Please, note, that is available since PHP 5.3