使用substr搜索数组的前三个字符

Question

I am making a simple zip code lookup for rates. The code below functions, basically if the first 3 characters from $zipcode are "962" ( or whatever is determined ) it echos the text. Is there a way to clean this up?

How can I make $zipcode look through a array to see if any of the conditions are true?

if (substr($zipcode, 0, 3) === '962' || substr($zipcode, 0, 3) === '963' || substr($zipcode, 0, 3) === '964' || substr($zipcode, 0, 3) === '964' || substr($zipcode, 0, 3) === '965' || substr($zipcode, 0, 3) === '966') {
echo "We do not ship FPO";
}

Answer 1

You could simply put list of unsupported zip prefixes into and array and check the prefix provided against this array.

$zip_prefix_no_ship = array('962', '963', '964', '965', '966');
$zip_prefix = substr($zip_code, 0, 3);
if(in_array($zip_prefix, $zip_prefix_no_ship)) {
    echo "We do not ship FPO"
}