douqie1816 2018-04-02 16:41
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I have got this issue:

Notice: Undefined offset: 1 in every row of $news_date[1].

Here are my code:

    }else if($news_date[1]==2){
    } //and so on..
$press_date=$news_date[1].', '.$news_date[0];

I stored date data with news_date field.

Please kindly suggestion How can I should do.

Thank you very much in advance.

*** Editable**** After ask via Stack now I have used these code to solve my problem. It is just using 3 lines. Thank you Adrian Preuss for your suggestion.

    $press_date=$rs['news_date']; // store data from DB
    $new_formatDate=date("M d, Y",strtotime($press_date));  // Set Date Month Year styles that I want
    $new_formatDate = strtoupper($new_formatDate);  // Make it to ALL CAP
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1条回答 默认 最新

  • donglu5612 2018-04-02 16:55

    You wan't to work with Date formats- Your problem is, you split the Date simply with explode - This way is not correct, because your splitted data has following format:

    [0] "2014"
    [1] "07"
    [2] "21"

    You check the splitted string (after splitting, each entry is also an string to) with integers:

    if("07" == 1) {

    The second problem is, you don't validate, if the data is set. The next problem is: You want to display only another date format - Please use PHP-based functions for formatting. Here are a sample for you:

    $press_date = '2014-07-21';
    print date('d. M Y', strtotime($press_date));

    Output: 21. Jul 2014

    $press_date = '2014-07-21';
    print date('l, d. F Y', strtotime($press_date));

    Output: Monday, 21. July 2014

    Informations about the output format can be found at

    本回答被题主选为最佳回答 , 对您是否有帮助呢?



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