drlhsfqoa350437979 2016-04-10 13:20
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PHP函数错误:注意:未定义的偏移量

I have simple function but got the error message : Notice: Undefined offset: 3 in

i checked the problem is in line : $newValue += $value[$i];

the answer of below function is "6" but error message still displayed.

<?php
function countMe($value) {

    $newValue = 0;

    for ($i=0; $i<=count($value); $i++) 
    {
        $newValue += $value[$i];
    }   
    return $newValue;
}   

$value[0] = 1;
$value[1] = 2;
$value[2] = 3;

echo countMe($value);
?>

I know the solution is just Suppress the error with the @ operator such as @countMe($value) but i want to know What's wrong with this function ?? Any help would be appreciated. Thanks

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2条回答 默认 最新

  • dqde43215 2016-04-10 13:26
    关注

    Indexes are from 0 to 2... your function should count to count() - 1:

     for ($i=0; $i<=count($value)-1; $i++)
    

    or

     for ($i=0; $i<count($value); $i++) 
    

    By the way... just use array_sum($value) to get the same result :)

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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