doujiang1001 2016-04-08 00:26
浏览 102
已采纳

在静态方法中创建当前类的对象 - PHP

I have some problems with my class Model and other classes so I made this simple example to explain my problem :

class person{

  public static $a = "welcome";

  public function __construct(){
                               }

  public static function getobject()
  {
      $v = new person();
      return $v;
  }

}

class student extends person{

  public static $b = "World";

}

$st = student:getobject();//this will return person object but I want student object

echo $st->$b; // There is an error here because the object is not student

So I want to know what to write instead $v = new person(); to get the object of the last inherited class.

  • 写回答

1条回答 默认 最新

  • drlnsli18864734 2016-04-08 00:29
    关注

    Use the late static binding's static keyword.

    public static function getobject()
    {
        $v = new static();
        return $v;
    }
    

    So, with student::getobject() you get an instance of student.

    To retrieve the static (but why?) $b propriety, you can do $st::$b, or simply student::$b.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥100 需求高精度PT100设计电路和算法
  • ¥15 单片机配网,继电器开关,广播
  • ¥60 Qcustomplot绘制实时动态曲线
  • ¥20 运用matlab画x-y图
  • ¥15 用idea运行项目,运行tomcat报错:断言失败
  • ¥15 Sqlserver查询链接服务器数据问题
  • ¥15 Bibtex4Word 引用中文文献
  • ¥20 用opencv c/c++ 转换成灰度图,然后做一下直方图均衡,输出mp4文件
  • ¥20 matlab中的双层数值积分
  • ¥50 服务器打印水晶报表问题