Im sorry if this has been answered before but I am new to PHP and MySQL and I can't figure this out.
Pretty much every time I alter my code to include an array I get a fatal error. What I am trying to do is display all the data in 3 columns from my table.
I have my site set up where you log in and I store that user's name as a "code" in a session. I have a table that has multiple user form entries that are differentiated by the user's code because in my form, I grab the code as a hidden field and add it to the entry in the table.
So far I have been able to isolate those entries by the users code, in one column I have the sum of all of the user's numerical data and I am able to echo this as a total.
I want the other 3 columns to display all the values in their columns and for each value have a line break in between them. And I am trying to print or echo these results in specific parts on a confirmation page.
I have seen examples with PDO using fetch_all and other examples of storing arrays but I can't seem to figure it out with my existing code.
Here is my existing code:
<?php
$user = *****;
$pass = *****;
$dbh = new PDO('mysql:host=localhost;dbname=*****', $user, $pass);
$stmt = $dbh->prepare("SELECT sum(price),part_number,location,price FROM products WHERE code = :usercode");
$stmt->bindParam(':usercode', $_SESSION['MM_Username']);
if ($stmt->execute()) {
$user = $stmt->fetch(PDO::FETCH_ASSOC);
}
?>
And here is where I want to display the results:
<table style="margin:0 auto;" cellspacing="7" width="100%">
<tbody>
<tr>
<td><?php echo $user['part_number']; ?></td><!--all column values-->
<td><?php echo $user['location']; ?></td><!--all column values-->
<td><?php echo $user['price']; ?></td><!--all column values-->
<td><?php echo "Total:", $user['sum(price)']; ?><br></td><!--this is ok-->
</tr>
</tbody>
</table>
