如何在php中比较三个数字时找到最高组合

Question

There are three numbers in set A {3,4,7} and in set B {2,4,7}.

It is not possible to get the result true because the the first numbers in a and b are not same.

But I need to get the result as true by comparing other two number and leaving the first number.

How is it possible to do it in PHP?

Answer 1

try this it will helps you.. it will display the 1 => for more number of combinations as same and 0 => for more of combination as different . in the below code the more number of combination as different so its returns 0.

<?php
$A = array(2,3,7,5,6);
$B = array(4,3,7,8,9);

$flagTrue = 0;
$flagFalse = 0;
for($i=0; $i < count($A); $i++)
{
    if($A[$i] == $B[$i])
    {
        $flagTrue=$flagTrue+1;
    }
    else 
    {
        $flagFalse=$flagFalse+1;
    }
}

$var_is_greater_than_two = ($flagTrue >= $flagFalse) ? 1 : 0;
echo $var_is_greater_than_two;
?>