drnmslpz42661 2014-03-19 05:45
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PHP与JavaScript:改变传入的数组的值会产生不同的结果

It was very difficult to come up with an informed title for this post.

Though PHP and JS are totally different languages, I am very surprised to find that altering an array passed into a function as an argument gives different results.

PHP

<?php 
function thing($arr) {
    $arr[2] = "WOOF";
}

$hello = array(1,2,3,4);
thing($hello);
print_r($hello);
// Array ( [0] => 1 [1] => 2 [2] => 3 [3] => 4 )
?>

Javascript

function thing($arr) {
    $arr[2] = "WOOF";
}

$hello = [1,2,3,4];
thing($hello);
console.log($hello);
// [1, 2, "WOOF", 4]

Which is "correct"?

Why is there a difference in results here? Why does JS accept that the argument is simply an alias to the original array, but PHP doesn't?

Which way is the most 'correct' -- and why?

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2条回答 默认 最新

  • doushifang4382 2014-03-19 05:47
    关注

    In javascript object are passed by reference So you are getting the result like this so said that both the result are true in their own domain.

    you can try this via console too..

    >>> var s = [1,2,3,4];
    undefined
    >>> var b = s;
    undefined
    >>> b;
    [1, 2, 3, 4]
    >>> s;
    [1, 2, 3, 4]
    >>> b[2] = "data";
    "data"
    >>> b;
    [1, 2, "data", 4]
    >>> s;
    [1, 2, "data", 4]
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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