dshqd84261 2009-05-19 14:28
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PHP打印日期变量格式

So this should be a real easy question but I can't seem to find a simple answer anywhere.

I'm patching up some PHP code (I'm not a PHP'er) and I have this variable $orderDate. How do I print this variable so that its just M/d/yy h:mm tt?

Update: So I looked around and saw what $orderDate is. Here's the code:

global $orderDate;
$orderDate = strftime('%c');
print("Order Date: ".date("M/d/Y h:M", $orderdate)."<br />");

so I get this for output:

Dec/31/1969 06:Dec

and should be getting today's date....

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  • douwo8358 2009-05-19 14:30
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    echo date("m/d/Y h:m", $orderDate);
    echo date("m/d/Y h:m", strtotime($orderDate)); // or this
    

    Depends on what $orderDate contains.

    Look into date() since it has there plenty of examples and is pretty simple to use.

    UPDATE:

    $orderDate = date("M/d/Y h:M");
    print("Order Date: ".orderDate ."<br />");
    

    Also check out to see if this works for you.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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