douao1579 2015-07-29 05:14
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Laravel 5.1中的empty where子句更喜欢雄辩的方法

i am looking to produce the following query in laravel 5.1 with eloquent method.

The mysql query is a follows

SELECT * FROM orders WHERE 1 = 1 ORDER BY o_date DESC LIMIT 25

No matter what i cant get the

WHERE 1 = 1

part working.

am new to laravel and pretty sure this is easy. but can't figure it out.

I have tried the following variations

$orders = orders::where('1', 1)->orderBy('o_date', 'desc')->take(25)->get();
$orders = orders::where(1)->orderBy('o_date', 'desc')->take(25)->get();
$orders = orders::where('1', '=', '1')->orderBy('o_date', 'desc')->take(25)->get();

but its not working. the query results is as shown below

> select count(*) as aggregate from `orders`
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2条回答 默认 最新

  • dongtuo0828 2015-07-29 07:07
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    Seems like (looking at 1=1) you need whereRaw

    $orders = orders::whereRaw("any clause u wish")->orderBy('o_date', 'desc')->take(25)->get();
    

    but if "any clause u wish" is not a VERY-VERY dinamical part u'd better look what else you can use

    http://laravel.com/api/5.0/Illuminate/Database/Query/Builder.html

    For the above example the below code works fine

    $orders = orders::whereRaw("1 = 1")->orderBy('o_date', 'desc')->take(25)->get();
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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