In Nginx, how can I select the bold part of the URL below? 2013 and 12 are relative to the date so the rule needs to be flexible to work future locations.
example.com/wp-content/uploads/2013/12/sometime.pdf
The end result should look something like: index.php?method=2013/12/sometime.pdf
Current rewrite rule
I have tried with the following but this will only return the last letter of the URL.
rewrite ^/wp-content/uploads/2013/12/sometime.pdf /index.php?method=$1
Thanks!
分享 This expression will rewrite anything in the uploads folder, without a known extension, and passes the two parts of the URL as required:-
rewrite ^/wp-content/uploads/(.*)\.(?!css|js|png|jpe?g|gif)(.*)$ /index.php?method=$1.$2
$1, i.e. the first "(.*)" is anything between /wp-content/uploads/ and the . of the file extension.
$2, i.e. the second "(.*)" is anything after the matched . of the file extension,
Negative look aheads are the trick here: (?!.....)
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