douyuefu1372
2012-04-19 20:10
浏览 123
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如何将动态添加的文本框(JavaScript)中的多个数据保存到MySQL数据库中?

I have been trying for this but no success. I am using PHP, HTML, JavaScript, and MySQL. Here is my HTML code:

<div id="Author">
    <LI>Author</LI> 
    <input type = "text" name="Author[]" value = "1. "/>
    <input type="button" value="+" id="Authorbutton" onclick="addAuthor()" />
</div>

If add button is clicked, another textbox will appear and user and put in another name. Here is my JavaScript:

var counter3 = 0;
function addAuthor() {
    // Get the main Div in which all the other divs will be added
    var mainContainer = document.getElementById('Author');

    // Create a new div for holding text and button input elements
    var newDiv = document.createElement('div');

    // Create a new text input
    var newText = document.createElement('input');
    newText.type = "text";
    //var i = 1;
    newText.name = "Author[]";
    newText.value = counter3 + 2 + ". ";

    //Counter starts from 2 since we already have one item
    //newText.class = "input.text";
    // Create a new button input
    var newDelButton = document.createElement('input');
    newDelButton.type = "button";
    newDelButton.value = "-";

    // Append new text input to the newDiv
    newDiv.appendChild(newText);
    // Append new button input to the newDiv
    newDiv.appendChild(newDelButton);
    // Append newDiv input to the mainContainer div
    mainContainer.appendChild(newDiv);
    counter3++;
    //i++;

    // Add a handler to button for deleting the newDiv from the mainContainer
    newDelButton.onclick = function() {
        mainContainer.removeChild(newDiv);
        counter3--;
    }
}

Here is my PHP code:

if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db($database, $con);



$sql="INSERT INTO savetest (type, number)
VALUES
('$_POST[type]','$_POST[Author]')";

if (!mysql_query($sql,$con))
  {
  die('Error: ' . mysql_error());
  }
echo "1 record added";

mysql_close($con);
echo "Thank you for submitting your details!";

I heard a lot of people can get this to work by using arrays, but the data I stored in the database is Array. It does not matter how many textboxes I've created, just Array.

Am I using the correct approach? Should I save this array of data in one database fields?

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1条回答 默认 最新

  • dpjpo746884 2012-04-20 09:40
    已采纳
    if (!$con){
       die('Could not connect: ' . mysql_error());
    }
    
    mysql_select_db($database, $con);
    
    $authors = $_POST['Author'];
    foreach($authors as $author) :
        $sql="INSERT INTO savetest (type, number) VALUES ('{$_POST['type']}','{$author}')";
    
        if (!mysql_query($sql,$con)){
           die('Error: ' . mysql_error());
        }
    endforeach;
    
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