I have a function in jquery which displays images on link click and also has to hide the image when the link is clicked again.
This is the code:
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7/jquery.min.js"></script>
<script>
var $j = jQuery.noConflict();
$j(document).ready(function(){
$j('.links').click( function(){
var linkclicked = this.id;
var url = $j(this).attr('href'),
image = new Image();
image.src = url;
image.onload = function () {
$j('#image-holder'+linkclicked).empty().append(image);
/* The above line shows the image on first click.
Adding slideToggle hides the image again */
};
image.onerror = function () {
$j('#image-holder'+linkclicked).empty()
.html('That image is not available.');
}
$j('#image-holder'+linkclicked).empty().html('Loading...');
return false;
});
});
function loadnow() {
}
</script>
</head>
<body>
<?php $topicid=1; ?>
<a href="myimages/red-brick-wall-texture.jpg" class="links" id="<?php echo $topicid; ?>" >Show image</a>
<div id="<?php echo 'image-holder'.$topicid; ?>"></div>
<?php $topicid=2; ?>
<br><a href="/myimages/gymicon.JPG" class="links" id="<?php echo $topicid; ?>" >Show image</a>
<div id="<?php echo 'image-holder'.$topicid; ?>"></div>
</body>
</html>
Please let me know where to write slideToggle as to enable show/hide function properly. There are two links here which show separate images. They are shown when clicked but the problem is to hide them on next click and make them
visible when clicked again and so on.
