需要算法和实现帮助 - 比较2个文件[关闭]

Question

My Project Purpose : There are 4 files. Each of them has different number of lines. Each line consists of a single or few words. Now, for each of these files, I want to count which other file has the maximum common words.

• eg. (',' is a new line )
• Input:
• File 1 Lines : A,B,C,D
• File 2 Lines : C,D,E,F
• File 3 Lines : A,E,C,G

• File 4 Lines : C,E,F,A

• Output :

• File 1 : Maximum common words is 2 and they are in the files : File 2 (C,D), File 3 (A,C) and File 4 (C,A).
• File 2 : Maximum common words is 3 and they are in the files : File 4 (C,E,F).
• File 3 : Maximum common words is 3 and they are in the files : File 4 (C,E,A).
• File 4 : Maximum common words is 3 and they are in the files : File 2 (C,E,F).

My logic :

1. Start
2. Read each line from file and store it in memory as a 1-D array (eg. array1[0] = "A", array1[1] = "B" and so on.
3. Since there are 4 files, I create 4 arrays = array1 to array4. Each of them will have the contents of their corresponding files.
4. Now I will compare the first words in the first array with the first word in the second array.
5. Now I will compare the first words in the first array with the second word in the second array and so on till the end on second array.
6. I will continue this till the last word in the last array.
7. When ever I found something was matching I will note down in a variable by incrementing 1.

Wish to know if this is the right of approaching this problem.

Or is there a better way to think at this problem?

Edits : 1. Forgot to add, Will be using php.

Answer 1

Should be easily done with array_intersect.