检查字符串末尾的字符串'（xx％）'

Question

How can I check if a string has any value like

(xx%)

at the end?

I would like to extract that value (remove it from the string and save the value in a variable)

Example:

Lorem ipsum (34%)

should become

$string = 'Lorem ipsum';
$value = 34;

Answer 1

Using capturing groups:

$original = 'Lorem ipsum (34%)';

if (preg_match('/(.*)\s*\((\d+)%\)$/', $original, $matched)) {
    $string = $matched[1];  // 'Lorem ipsum'
    $value = $matched[2];   // '34'
} else {
    // do something else if it does not match.
}