dongyangzhi0687 2014-10-07 05:02
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在非对象DateTime上调用成员函数format()

This problem might be common but it seems like I can't find out what I did wrong.

I have two variables the date and time from database which I think is in UTC format and I need to convert to AEST;

$date = message['date']; //25/09/2014
$time = message['time']; //9:00:00

$combined_time = $date . " " . $time;
$schedule_date = DateTime::createFromFormat("Y-m-d H:i:s",$combined_time ,new DateTimeZone("Australia/Melbourne"));
return $schedule_date->format("jS-A-Y H:i:s T");

I got Call to a member function format() on a non-object exception.

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  • duanchi5078 2014-10-07 05:12
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    You should use ("d/m/Y h:i:s"):

    $schedule_date = DateTime::createFromFormat("d/m/Y h:i:s", $combined_time , new DateTimeZone("Australia/Melbourne"));
    

    The given format is wrong because your date-time is as 25/09/2014 9:00:00. Check this example.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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