在PHP中解析解码的JSON

Question

I have managed to decode some JSON in PHP successfully (not as painful as I thought), but it's been such a long time since I've done any real PHP, my brain has drawn a blank on the following.

The decoded json looks like this

[Array]
item {
      [0]
      {
         [live]=>
         [name]=>Paul
         [value]=>10
      }
      [1]
      {
         [live]=>1
         [name]=>Fred
         [value]=>32
      }

and so on

The problem I'm having is this - I'm trying to iterate through the structure to test first if live==1 and then if it's the first live name, to output it as a selected value to a HTML drop down.

I'm currently trying like this

$t = 0;
$count = 0;
foreach($decode['items'] as $option=>$value)
{
print_r("option = $option
");
    if ($option=>isLive == 1)   
{
    print_r("isLive is true for $option[$count]['names']
");
        if ($t == 0)
        {
        echo "<option value=$option[name] selected>$value[name]</option>";
        $t = 1;
    }
    else
        echo "<option value=$option[name]>$value[name]</option>";
    }  
    else 
    {
    print_r("isLive is false for $option[$count]=>name
");
    }
    $count++;
}

the problem is that I don't seem to be able to get the if statement correct for this to work. This is probably a seriously simple problem and will no doubt make me face palm, but I could do with a pointer in the right direction here!

Answer 1

If the json is like you showed us you could not iterate over anything with your foreach because your array does not contain a key named items.

Using the provided structure this should do the trick:

foreach($decode["item"] as $item) {
    if($item->live == 1) {
        ...
    } else {
        ...
    }
}

If $item is not an object use $item['live'] instead.

P.S.: You should really turn error_reporting on. $option=>isLive is no valid syntax.