如何使用get方法来执行PHP的不同功能。

Question

I wrote a simple php file to open different websites using different URLs. PHP code is here.(it's file name is user.php)

<?php 

$id =  $_GET["name"] ;

 if ($id=joe) {

header('Location: http://1.com');
}

 if ($id=marry) {

header('Location: http://2.com');
}

 if ($id=katty) {

header('Location: http://3.com');
}

?> 

I used those 3 methods to call php file.

1.http://xxxxxx.com/user.php?name=joe
2.http://xxxxxx.com/user.php?name=marry
3.http://xxxxxx.com/user.php?name=katty

But php file opens only http://3.com at every time.How to fix this.? how to open different websites for each names.?

Answer 1

Your comparison is wrong. joe, marry and katty are string type

<?php 

$id =  $_GET["name"] ;

 if ($id=='joe') { //<--- here

header('Location: http://1.com');
}

 if ($id=='marry') { //<--- here

header('Location: http://2.com');
}

 if ($id=='katty') { //<--- here

header('Location: http://3.com');
}

?> 

Here is PHP comparison operator description. http://php.net/manual/en/language.operators.comparison.php