duandang6111 2018-05-03 18:51
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在自制的PHP MVC框架中呈现视图文件

I've developed My Own MVC Framework using php. I call view files in controller like:

include('../view/home.php'); 

but I want to use it like:

$this->view('home');

How can I define common function for that where I can just pass view name i.e home only and it will do include view file without passing the full file path?

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  • dongmi4035 2018-05-03 19:02
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    No one could answer you without seeing your codes really. But this should be my approach. You should have a class that all your controllers extend. Lets say that you have class Controllers and all your controllers extend it.

    Then you may have a method inside the class named view($view_name).

    public function view($view_name){
       include $some_path . '/' . $view_name . '.php';
    }
    

    then whenever you call view by $this->view it will include the view if it exists. This is not the best approach and I did not test the code. I just wanted to show you the path

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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