如何从存储在变量中的日期中减去月份？

Question

If I use this way I can get what I want :

echo Date("m/Y", strtotime("04/2014 -1 Month"));
// 03/2014

but I need to generalize this to subtract from unknown date like this :

$date1 = date("m/Y", strtotime("+1 month"));
$date = date("m/Y", strtotime("".$date1." -$f month"));

I get wrong answers for date it show 01/1970 I want to know is it possible to use the date variable inside strtotime ? and is my way to use it right or wrong?

Answer 1

You can also use modify function.

$date = new DateTime('2014-04-01');
$date->modify('-1 month');
echo $date->format('m-Y');