检查是否设置了功能参数

Question

I have a function that loads a butterfly image.

There are 3 possible parameters: colour, angle and position

The last one is always explicitly set, but the first 2, if not set, are determined with a random number. This means that the function will always load a nice randomly coloured and angled butterfly, unless specifically set.

I have this

function randombf ($randbf,$randangle,$position) {
    $randbf = rand(1,4);
    $randangle = rand(1,4);
    echo '<div class="bf '.$position.'" style="background:url(\'images/bf_'.$randangle.'_'.$randbf.'.png\');"></div>';
}

Now the problem I have is that I would only like the random to be set if the parameters aren't passed.

Something like:

if(!$randbf) {
    $randbf = rand(1,4);
}

But that doesn't work if I pass

randombf('1','2','whatever')

It performs the random regardless.

What am I doing wrong?

Answer 1

You should change the order of your parameters. Put position first because it will be always specified. If you do it this way, you will be able to write randombf(12) or randombf(12, 1, 2) or even randombf(12, 1).

Omitted parameters will be set to null (you can specify anything else if you want, but only scalar values), so you only have to check if the var is_null().

function randombf ($position, $randbf = null, $randangle = null) {
    if (is_null($randbf)) $randbf = rand(1,4);
    if (is_null($randangle)) $randangle = rand(1,4);
    echo '<div class="bf '.$position.'" style="background:url(\'images/bf_'.$randangle.'_'.$randbf.'.png\');"></div>';
}

Let me incorporate the link @Matt Ball has posted into my answer:

Default function arguments