只有在没有抛出异常的情况下，才能在try块之外执行代码的最简洁方法

Question

This question is about the best way to execute code outside of try block only if no exception is thrown.

try {
    //experiment
    //can't put code after experiment because I don't want a possible exception from this code to be caught by the following catch. It needs to bubble.
} catch(Exception $explosion) {
    //contain the blast
} finally {
    //cleanup
    //this is not the answer since it executes even if an exception occured
    //finally will be available in php 5.5
} else {
    //code to be executed only if no exception was thrown
    //but no try ... else block exists in php
}

This is method suggested by @webbiedave in response to the question php try .. else. I find it unsatisfactory because of the use of the extra $caught variable.

$caught = false;

try {
    // something
} catch (Exception $e) {
    $caught = true;
}

if (!$caught) {

}

So what is a better (or the best) way to accomplish this without the need for an extra variable?

Answer 1

One possibility is to put the try block in a method, and return false if an exception is cought.

function myFunction() {
    try {
        // Code  that throws an exception
    } catch(Exception $e) {
        return false;
    }
    return true;
}