迭代通过xpath求值返回

Question

How is correct wayt to interate all elements return by xpath->evaluate?

i have that structure:

<?
$html = '
<div class="xGh" style="background-image: url(\'name_file0.jpg\');"></div>
<div class="xGh" style="background-image: url(\'name_file1.jpg\');"></div>
<div class="xGh" style="background-image: url(\'name_file2.jpg\');"></div>
<div class="xGh" style="background-image: url(\'name_file3.jpg\');"></div>
';

libxml_use_internal_errors(true);
$dom = new domDocument('1.0', 'utf-8'); 
$dom->loadHTML($html); 
$dom->preserveWhiteSpace = false; 
$xpath = new DOMXPath($dom);

$img = $xpath->evaluate('substring-before(substring-after(//div[@class=\'xGh\']/@style, "background-image: url(\'"), "\')")');    

echo $img;//name_file0.jpg

edit

With that loop in can iterate my object, but not correct result:

<?
$html = '
<div class="xGh" style="background-image: url(\'name_file0.jpg\');"></div>
<div class="xGh" style="background-image: url(\'name_file1.jpg\');"></div>
<div class="xGh" style="background-image: url(\'name_file2.jpg\');"></div>
<div class="xGh" style="background-image: url(\'name_file3.jpg\');"></div>
';

libxml_use_internal_errors(true);
$dom = new domDocument('1.0', 'utf-8'); 
$dom->loadHTML($html); 
$dom->preserveWhiteSpace = false; 
$xpath = new DOMXPath($dom);

$items = $xpath->query('//div[@class="xGh"]');
for($i = 0; $i < $items->length; $i++)
{   $ci = $xpath->evaluate("substring-before(substring-after(//*[@class=\"xGh\"]/@style, \"background-image: url('\"), \"')\")");
echo $ci;
}//name_file0.jpgname_file0.jpgname_file0.jpgname_file0.jpg

The output needed is :

name_file0.jpgname_file1.jpgname_file2.jpgname_file3.jpg

Where is the correct place to put one count iterator in that loop, to give sequence files not the same?

How iterate to return others?

Answer 1

Let's try this:

<?php

$html = '
<div class="xGh" style="background-image: url(\'name_file0.jpg\');"></div>
<div class="xGh" style="background-image: url(\'name_file1.jpg\');"></div>
<div class="xGh" style="background-image: url(\'name_file2.jpg\');"></div>
<div class="xGh" style="background-image: url(\'name_file3.jpg\');"></div>
';

libxml_use_internal_errors(true);
$dom = new DOMDocument('1.0', 'utf-8');
$dom->loadHTML($html);
$dom->preserveWhiteSpace = false;
$xpath = new DOMXPath($dom);

$divs = $xpath->query('//div[@class=\'xGh\']/@style');

/* @var DOMAttr $div */
foreach ($divs as $div) {
    preg_match("/url\('(.*)'\)/", $div->nodeValue, $matches);

    if (!isset($matches[1])) {
        continue;
    }
    $url = $matches[1];

    // name_file0.jpg, ...
    echo $url . "
";
}