dongxia026531 2017-05-23 18:14
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golang-用数字代替字符串

I'm trying to run this piece of code to replace a character of a string by a random number:

//Get the position between 0 and the length of the string-1  to insert a random number
    position := rand.Intn(count - 1)
    strings.Replace(RandomString,)

    fmt.Println("Going to change the position number: ", position)
    //Insert a random number between [0-9] in the position
    RandomString = RandomString[:position] + string(rand.Intn(9)) + RandomString[position+1:]

When this is executed, the output is:

I was going to generate..  ljFsrPaUvmxZFFw
Going to change the position number:  2
Random string:  lsrPaUvmxZFFw

Could anyone help me about inserting that number inside the desired string position? I didn't find any duplicate case of this.

Thanks in advance.

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  • doujuanju3076 2017-05-23 18:21
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    There are no printable characters in the range [0, 9). If you want an ascii value, start at 48 ('0'). You probably want to include 9 too, so use rand.Intn(10)

    string('0' + rand.Intn(10))
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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