从Go中的可变参数创建带有可选字段的类型

Question

I am learning Go right now and would like to initialize a type using variadic arguments without using reflection. Is it possible?

Here an example:

type MyType struct {
    field1 string
    field2 string
    ...
    fieldN string
}

func CreateMyType(arguments ...string) *MyType {
    inst := MyType{arguments...}  // does not work, is there any other way???
    return &inst
}

Note It makes me really sad, that the question is downvoted, where I ask legitimate things and try to learn out of them :(

Answer 1

It's possible with a little bit of code:

func CreateMyType(arguments ...string) *MyType {
    var m MyType
    switch len(arguments) {
    case 3:
        m.field3 = arguments[2]
        fallthrough
    case 2:
        m.field2 = arguments[1]
        fallthrough
    case 1:
        m.field1 = arguments[0]
    }
    return &m
}

playground example