用静态函数计算学生平均成绩：此代码中25行，我将对象作为函数形参，编译器说这行有问题，请问该怎么改，我想不修改写法把bug de掉，谢谢大家帮忙指点一下

Question

#include<iostream>
using namespace std;
class Student
{
    public:
        Student(int n,int s):number(n),score(s){}       //构造函数初始化
        static float average();                                    //声明静态函数
        void data();                                                   //声明成员函数
    private:
        int number,score;                                        
        static int Average,sum;                                 //静态数据成员Average，sum
};


int Student::Average=0;                                   //静态数据成员初始化
int Student::sum=0;

void Student::data()
{
    cout<<"Please input data:"<<endl;
    cin>>number>>score;         
}

float Student::average(Student &stu)
{
    int i,j;
    cout<<"The number of students that you want to calculate is:"<<endl;
    cin>>j;
    for(i=0;i<j;j++)
        {
        sum=sum+stu[i].score;
        }
    Average=sum/i; 
    return(Average);
}

int main()
{
    Student stu[3]={Student(1,90),Student(2,91),Student(3,92)};
    //对象数组初始化
    int k;
    for(k=0;k<3;k++)
        {       
            stu[k].data();
        }
    average();
    return 0;
}

Answer 1

语法问题

average 函数声明与定义不符合;
line 7 和line 23行

同时你average函数输入的是一个student,但是你在里面却想要把它当做一个数组~

如果你要改,那么你就需要把average声明为:

static float average(Student stu[],int lengh);

定义变更为:

float Student::average(Student stu[], int lengh)  //###修改函数传参###
{
    int i, j;
    cout << "The number of students that you want to calculate is:" << endl;
    cin >> j;
    for (i = 0; i < j && i < lengh; j++)//####大小做限定不能超过他本来的大小####
    {
        sum = sum + stu[i].score;
    }
    Average = sum / i;
    return (Average);
}