这样嵌套循环，用什么标签<c:foreach>还是<logic>?第二个循环是根据第一个循环条件获得的

Question

package com.svse.struts.action;

import java.util.List;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import org.apache.struts.actions.DispatchAction;

import com.svse.struts.entity.TBoard;
import com.svse.struts.entity.TType;
import com.svse.struts.form.BoardForm;
import com.svse.struts.impl.BoardImpl;
import com.svse.struts.impl.TypeImpl;
import com.svse.struts.service.BoardService;
import com.svse.struts.service.TypeService;

public class BoardAction extends DispatchAction
{

    private BoardService boardService = new BoardImpl();
    private TypeService typeService = new TypeImpl();

    /***
     * 
     */
    public ActionForward all(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response)
    {
        BoardForm boardForm = (BoardForm) form;

//怎么在demo.jsp页面中显示所查询的type.getTName()和board.getBName（）的值，向这样嵌套循环，用什么标签<c:foreach>还是<logic>?第二个循环是根据第一个循环条件获得的
        List<TType> typeList = typeService.getAllType();
        for (TType type : typeList) {
            System.out.println(type.getTName());
            List<TBoard> title = boardService.getAllTitle(type.getTId());//根据ID查询所有版面信息

            request.setAttribute("title", title);
            for (TBoard board : title) {
                System.out.println("________________"+board.getBName());
            }
        }
        
        return new ActionForward("/user/demo.jsp",false);//请求转发
    }
}

Answer 1

应该是这样吧
[code="java"]



显示内容，既可以获取集合1的，也可以获取集合2的
/c:if
/c:forEach
/c:forEach
[/code]