题目如下，请找出代码错误，改了十多次了，救命qwq

Question

#include <stdio.h>

int main()
{
int K;
scanf("%d",&K);
while(K--)
{
int y,a,b,c;
float x;
scanf("%d %d %d",&a,&b,&c);
if(c==1){
if(a==b!=0){
printf("0\n");
goto end;
}
if(a==b==0){
printf("1\n");
goto end;
}
if(a!=b){
printf("None\n");
goto end;
}
}else if(c==0){
if(a==0&&b!=0){
printf("0\n");
goto end;
}else{
printf("None\n");
goto end;
}
}
else{
x=(b*c-a)/(1.0-c);
y=(int)x;
if(x<0||x-y>0){
printf("None\n");
goto end;
}
printf("%d\n",y);
}
end:;
}
return 0;
}

Answer 1

修改如下，供参考：

#include <stdio.h>
int main()
{
    int K;
    scanf("%d", &K);
    while (K--)
    {
        int y, a, b, c;
        float x;
        scanf("%d %d %d", &a, &b, &c);
        if (c == 1) {
            if (a != 0 && b != 0 && a == b) {
                printf("0\n");
                //goto end;
            }
            if (a == 0 && b == 0) {
                printf("1\n");
                //goto end;
            }
            if (a != b) {
                printf("None\n");
                //goto end;
            }
        }
        else if (c == 0) {
            if (a == 0 && b != 0) {
                printf("0\n");
                //goto end;
            }
            else {
                printf("None\n");
                //goto end;
            }
        }
        else {
            x = (b * c - a) / (1.0 - c);
            y = (int)x;
            if (x < 0 || x - y>0) {
                printf("None\n");
                //goto end;
            }else
                printf("%d\n", y);
        }
    //end:;
    }
    return 0;
}