求解，Python 程式碼要怎麼修改

Question

請問這程式碼要怎麼寫成
輸入一個數後
直接輸出

我現在這個程式碼
是還需要多按一次輸入才能輸出

例如
我輸入25
直接輸出22

輸入23456
直接輸出1365

 
def read_input():
    numbers = []
    max_length = 0
    while True:
        num = input()
        if not num:
            break
        numbers.append(num)
        if len(num) > max_length:
            max_length = len(num)
    return numbers, max_length
numbers, max_length = read_input()
 
import functools
@functools.lru_cache()
def get_ladder_number_count_for_length(length):
    ans = 0
    for j in range(9):
        ans += matrix[length][j] 
    return ans
def make_triangle(length):
    matrix = [[0]*9 for _ in range(length)]
    for i in range(9):
        matrix[0][i] = 1
    for i in range(length):
        matrix[i][0] = 1
    for i in range(1,9):
        for j in range(1,length):
            matrix[j][i] = matrix[j-1][i] + matrix[j][i-1]
    return matrix
matrix = make_triangle(max_length)
 
def answer(numbers, matrix):
    for number in numbers:
        ans = 0
        length = len(number)
        length_minus_one = length-1
        for i in range(length_minus_one):
            ans += get_ladder_number_count_for_length(i)
        for sequence, digit in enumerate(number):
            forming_ladder_on_left = True
            if sequence != 0:        
                if int(number[sequence-1]) > int(number[sequence]):
                    forming_ladder_on_left = False
            if forming_ladder_on_left is True:
                left_ind = sequence-1
                if left_ind < 0:
                    left_num = 1
                else:
                    left_num = int(number[left_ind])
                for i in range(left_num, int(digit)):
                    ans += matrix[length-1-sequence][-i]
            else:
                break
        if forming_ladder_on_left:
            ans+=1
        print(str(ans))
answer(numbers, matrix)
 

Answer 1

你自己在代码中设置的，只有输入的不是数字才跳出

def read_input():
    numbers = []
    max_length = 0
    num = input()
    numbers.append(num)
    if len(num) > max_length:
        max_length = len(num)
    return numbers, max_length