选择用哪一种非线性回归模型？

Question

选择用哪一种非线性回归模型？
怎么进行选择的啊？
根据图形还是？
感谢！

Answer 1

倒幂函数曲线y = a + b ⋅ 1 x y=a+b \cdot \dfrac{1}{x}y=a+b⋅
x
1
​
型
令x ′ = 1 x {x}'=\dfrac{1}{x}x
′
=
x
1
​
, 则得y = a + b ⋅ x ′ y=a+b \cdot {x}'y=a+b⋅x
′
.
双曲线1 y = a + b ⋅ 1 x \dfrac{1}{y}=a+b \cdot \dfrac{1}{x}
y
1
​
=a+b⋅
x
1
​
型
令x ′ = 1 x , y ′ = 1 y {x}'=\dfrac{1}{x}, {y}'=\dfrac{1}{y}x
′
=
x
1
​
,y
′
=
y
1
​
, 则得y ′ = a + b ⋅ x ′ {y}'=a+b \cdot {x}'y
′
=a+b⋅x
′
.
幂函数曲线y = d ⋅ x b y=d \cdot x^by=d⋅x
b
型
令y ′ = I n y , x ′ = I n x , a = I n d {y}'=Iny, {x}'=Inx, a=Indy
′
=Iny,x
′
=Inx,a=Ind, 则得y ′ = a + b x ′ {y}'=a+b{x}'y
′
=a+bx
′
.
指数曲线y = d ⋅ e b x y=d \cdot e^{bx}y=d⋅e
bx
型
令y ′ = I n y , a = I n d {y}'=Iny, a=Indy
′
=Iny,a=Ind, 则得y ′ = a + b x {y}'=a+bxy
′
=a+bx.
倒指数曲线y = d ⋅ e b x y=d \cdot e^{\dfrac{b}{x}}y=d⋅e
x
b
​

型
令y ′ = I n y , x ′ = 1 x , a = I n d {y}'=Iny, {x}'=\dfrac{1}{x}, a=Indy
′
=Iny,x
′
=
x
1
​
,a=Ind, 则得y ′ = a + b x ′ {y}'=a+b{x}'y
′
=a+bx
′
.
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原文链接：https://blog.csdn.net/wumian0123/article/details/81677076