C#winform要如何把web api联合在一起实现这个功能呢？

Question

需要实现的功能：对接口发一个pwd+data，我返回一个code和msg，然后把data展示到winform界面上（使用什么控件呢？，要怎么触发呢？怎么写代码能把data拿过来呢？）
这是我写的控制器代码，后面不知道怎么写了

using Microsoft.AspNetCore.Http;
using Microsoft.AspNetCore.Mvc;
using Microsoft.Extensions.Logging;

namespace PopUpByMessage.Controllers
{
    [Route("api/[controller]")]
    [ApiController]
    public class MyWebApiController : ControllerBase
    {
        private readonly ILogger<MyWebApiController> _logger;
        public MyWebApiController(ILogger<MyWebApiController> logger)
        {
            _logger = logger;
        }
        [HttpPost("[action]")]
        public IActionResult SayHello(string pwd, string data)
        {
            if (pwd != "1")
            {
                object obj = new
                {
                    code = "0",
                    msg = "请求失败"
                };
                return new JsonResult(obj);
                //return new BadRequestResult();
            }
            else
            {
                object obj = new
                {
                    code = "1",
                    msg = "请求成功"
                };
                return new JsonResult(obj);
            }
        }
    }
}

这是form1界面的代码

    public partial class Form1 : Form
    {
        private Lazy<IHost> webhost = new Lazy<IHost>(() => { return CreateHostBuilder().Build(); });
        public static IHostBuilder CreateHostBuilder() =>
            Host.CreateDefaultBuilder()
                .ConfigureWebHostDefaults(webBuilder =>
                {
                    webBuilder.UseKestrel(o => { o.ListenAnyIP(9527); });
                    webBuilder.UseStartup<Startup>();
                });
private async void button1_Click(object sender, EventArgs e)
        {
            await webhost.Value.StartAsync();
            MessageBox.Show("启动成功！");
        }

Answer 1

很对控件啊
textbox两个分别显示
datagridview两列