douhe5092 2012-04-17 22:57
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php匿名函数在php 5中

I've been using callback function like this:

private function make_f($arg1, $arg2)
{
    $callback =
        function ($my_var) use ($arg1, $arg2)
        {
            return $my_var  * $arg1 * arg2;
        };
    return $callback;
}

It supports by PHP 5.3.0 but my hosting provider has PHP 5.2.6 so it doesn't work. Is there any way to repair this somehow?

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  • duangong1979 2012-04-17 23:04
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    That really depends on what $arg is. For any possible value of $arg, I can only come up with something like this:

    public static $arguments = array();
    
    private function make_f($arg)
    {
        $variable_name = uniqid();
    
        ThisClass::$arguments[$variable_name] = $arg; // Replace ThisClass with the name of the actual class
    
        $callback = create_function('$my_var', 'return $my_var * ThisClass::$arguments[\'' . $variable_name . '\'];');
    
        return $callback;
    }
    

    Here's a demo.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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