PHP DOM如何在子项包含标记和文本节点时删除包装标记

Question

Given this markup

<badtag>
  This is the title and <em>really</em> needs help
<badtag>

I need to remove the wrapper, but do it without losing the tag, which is what happens if I simply do something like:

dom->createTextNode(currentNode->nodeValue)

I've tried the following, but it's not quite working and I want to make sure I'm on the right track and not missing an easier way. I do note that I need to add iteration when I hit a tag in the switch statement (rather than #text) so that I get the contents of the tag (such as with the tag).

      $l = $origElement->childNodes->length;
      $new = [];
      for ($i = 0; $i < $l; ++$i) {
        $child = $origElement->childNodes->item($i);
        switch ($child->nodeName) {
          case '#text':
            $new[] = $dom->createTextNode($origElement->textContent);
            break;
          default:
            $new[] = $child;
            break;
        }
      }
      foreach ($new as $struct) {
        $parentNode->insertBefore($struct, $origElement);
      }
      $origElement->parentNode->removeChild($origElement);

Answer 1

I've created something which creates a clone of the content of the node you want to remove. It didn't seem to like just moving the nodes, and when I use cloneNode instead, the new version seemed a lot cleaner.

<?php
error_reporting ( E_ALL );
ini_set ( 'display_errors', 1 );

$xml = <<<EOB
<DATA>
<badtag>
  This is the title and <em>really</em> needs help
</badtag>
</DATA>
EOB;

$dom = new DOMDocument();
$dom->loadXML($xml);

$origElement = $dom->getElementsByTagName("badtag")[0];
$newParent = $origElement->parentNode;
foreach ( $origElement->childNodes as $child ){
    $newParent->insertBefore($child->cloneNode(true), $origElement);
}
$newParent->removeChild($origElement);
echo $dom->saveXML();

For the small sample I've used, the output is...

<?xml version="1.0"?>
<DATA>

  This is the title and <em>really</em> needs help

</DATA>