C++——LeetCode——member access within misaligned address

Question

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode() : val(0), next(nullptr) {}
 *     ListNode(int x) : val(x), next(nullptr) {}
 *     ListNode(int x, ListNode *next) : val(x), next(next) {}
 * };
 */

class Solution {
public:
    ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
       ** ListNode* l = new ListNode();**
        int c=0; //进位位
        int val =0; //存放当前位置运算所得
        
        ListNode* p1 = l1;
        ListNode* p2 = l2;
        ListNode* p = l;
         
        if(p1==nullptr)
        {
            return l2;
        } 

        if(p2==nullptr)
        {
            return l1;
        } 

        //处理完较短的表后会跳出循环
        while(true)
        { 
           val =p1->val + p2->val+c;
           p->val = val % 10;
           c = val / 10;
           if(p1->next!=nullptr&&p2->next!=nullptr)
           {
              p1 = p1->next;
              p2 = p2->next;
              ListNode node;
              ListNode* temp = &node;
              p->next = temp;
              continue;
           }
           break;
        }
        
        //继续用进位位处理较长的表，不知道就直接两个指针一起处理
        while(p1->next!=nullptr)
        {
              ListNode node;
              ListNode* temp = &node;
              p->next = &node;
              p = temp;

              p1=p1->next;
              val = p1->val + c;
              p->val = val%10;
              c = val/10;
              //有进位未处理时
              if(c!=0&&p1->next==nullptr)
              {
                  ListNode node2;
                  temp = &node2;
                  temp->val=c;
                  p->next = temp;
              }
        }
        
        while(p2->next!=nullptr)
        {
              ListNode node;
              ListNode* temp = &node;
              p->next = temp;
              p = temp;

              p2=p2->next;
              val = p2->val + c;
              p->val = val%10;
              c = val/10;
              //有进位未处理时
              if(c!=0&&p2->next==nullptr)
              {
                  ListNode node2;
                  temp = &node2;
                  temp->val=c;
                  p->next = temp;
              }
        }
        return l;
    }
};

Line 15: Char 16: runtime error: member access within misaligned address 0x00000000000d for type 'ListNode', which requires 8 byte alignment (ListNodeUtils.cpp)
0x00000000000d: note: pointer points here

SUMMARY: UndefinedBehaviorSanitizer: undefined-behavior ListNodeUtils.cpp:24:16

请大家帮忙看下，不懂为什么会出现member access within misaligned address的问题，查了之前的类似问题，但是都是说结构体内的指针没有初始化，但是尝试之后还是一样的问题，而且结构体定义中不是已经有了初始化的参数列表么？

Answer 1

ListNode node;
              ListNode* temp = &node;
              p->next = &node;

你这个代码块是要干啥呢？