从远程站点调用Json输出

Question

I want to show this json url output in table over here which is producing error.

The line which the error is point is this

if ( isset($_GET['page'])=='home' && 
     $_GET['page']=='home' )
         include("http://midsweden.gofreeserve.com/proj/api.php?identifier=123&format=json"); 

The error produced is:

Warning: include() [function.include]: URL file-access is disabled in the server configuration in /www/zxq.net/a/c/r/acreo/htdocs/proj/index.php on line 65

Answer 1

Looks like you need to set allow_url_fopen = On in your php.ini file.

Or at runtime, you can do

ini_set("allow_url_fopen", "on");

By default, PHP disables the ability to call remote files via URL with fopen(), file_get_contents(), and the like.

If you don't have access to ini_set() but have .htaccess you can also try setting it in there. See http://davidwalsh.name/php-values-htaccess.

# .htaccess
php_value allow_url_fopen 1