PHP加密问题

Question

A quick and dirty experiment.

I put this code into a .php file and loaded it from my web host.

The result was "It works!" but.. why? Should it have failed? I was following Example #1 from here: http://php.net/manual/en/function.crypt.php

<?php
$pass1 = "thetimeshallwhintercows";
$salt = "temperpedic";

$crypt_pass = crypt($pass1, $salt);

if($crypt_pass == crypt("thetimeshallwhintercowz", $crypt_pass))
{
    print("It works!<br/>");
    print( $crypt_pass  );
    print("<br/>");
    print(crypt("thetimeshallwhintercowz", $crypt_pass));
}
else
{
    print("try again....");
}

?>

Answer 1

You should have a look at this answer to a similar question. the crypt() function requires that you have a correctly formatted salt. While temperpedic is a valid salt (sort of) it's not really a correctly formatted salt.

If you have a look at the PHP documentation for the crypt() function there are a few examples of using crypt() with different hash types. Have a look at these examples.

Remember, with crypt for modern web applications, you should be using at least SHA-256.

<?php
$pass1 = "thetimeshallwhintercows";
$salt = "temperpedic";

echo 'SHA-256:      ' . crypt($pass1, '$5$rounds=5000$' . $salt . '$') . "
";
echo 'SHA-256:      ' . crypt($pass1, '$5$rounds=5000$' . $salt . 'extra$') . "
";
echo 'SHA-256:      ' . crypt($pass1, '$5$rounds=5000$' . $salt . 'evenextra$') . "
";

?>

tim@roflcopter /tmp $ php lol.php
SHA-256:      $5$rounds=5000$temperpedic$4g0qFd4Oqr/O.8aZMPiyrO9x5VUaQt14eXPOMr5asK2
SHA-256:      $5$rounds=5000$temperpedicextra$3BF4dmqrCBuY2UtQpuhxXm4t4KGp1M9OoJPrskM490/
SHA-256:      $5$rounds=5000$temperpedicevene$jBsGNFGSAbuL8hdcXsZjHRrH6u4qnXb1bAJ.TOR32A2