php if语句用于显示某些html块

Question

I am currently trying to check my db table to see if a user's level is equal to or less than 10, if so then show an entire html list, if not and is equal or less than 5 show only the remaining part of the list. Here's where I started:

<?php

$levels = mysql_query("SELECT level FROM users");
  if ($levels <= 10) {

?>

html list

<?php 

if ($levels <= 5)

?>

html list

<?php

}

?>

I am trying to wrap my head around it, I just can't seem to get it.

Answer 1

$result = mysql_query(sprintf("SELECT level FROM users WHERE user_id = %d", $current_user_id));
if (list($level) = mysql_fetch_array($result)) {
  if ($level <= 5) { 
    // whatever
  }
  elseif ($level <= 10) {
    // whatever
  }
  else {
    // whatever
  }
}

Does that clear it up at all? You need to supply the ID of the current user, and then you need to actually retrieve the value from the $result. The $result is a variable of type resource, and you have to work on it with functions designed to do so.