duanke6057 2017-09-12 14:00
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php foreach组元素具有相同的值

I have an array that looks like this:

array (size=6)
  0 => 
    array (size=3)
      'name' => string 'Umber' 
      'reason' => string 'No data' 
      'id' => string '12'
  1 => 
    array (size=3)
      'name' => string 'Jakar' 
      'reason' => string 'Wrong format' 
      'id' => string '12'
  2 => 
    array (size=3)
      'name' => string 'Lane'
      'reason' => string 'No data'
      'id' => string '12' 
  3 => 
    array (size=3)
      'name' => string 'Jake' 
      'reason' => string 'Not found' 
      'id' => string '13' 
  4 => 
    array (size=3)
      'name' => string 'Jame' 
      'reason' => string 'Wrong name'
      'id' => string '13'
  5 => 
    array (size=3)
      'name' => string 'Joe' 
      'reason' => string 'No data' 
      'id' => string '13' 

What I want to do is group these elements in a table row if the same id value:

12 | No data, wrong format, No data
13 | Not found, Wrong name, No data

I know I have to use foreach for this one but the logic for grouping these elements in a single row is beyond me. Any help would be appreciated. Thanks in advance. I've started with this.

foreach($a as $value){
echo $value['id'] . ' ' . $value['reason'];
}
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2条回答 默认 最新

  • drouie2014 2017-09-12 14:04
    关注

    First group elements to subarrays, then output each subarray:

    $groups = [];
    foreach($a as $value){
        if (!isset($groups[$value['id']])) {
            $groups[$value['id']] = [];
    
            // update
            $groups[$value['id']] = [
                'names' => [],
                'reasons' => [],
            ];
        }
        $groups[$value['id']][] = $value['reason'];
    
        // update
        $groups[$value['id']]['names'][] = $value['name'];
        $groups[$value['id']]['reasons'][] = $value['reason'];
    }
    
    foreach ($groups as $key => $value) {
        echo $key . ' | ' . implode(', ', $value);
    
        // update
        echo $key . ' | ' . implode(', ', $value['names']) . ' | ' . implode(', ', $value['reasons']);
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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