检查foreach中的每个if语句

Question

Why my if-statement not checking each array inside foreach ? If someone already choose same kind of value, I want to disable it from select2 value, here's my code looks like :

function get_status_cab()
    {
        $status=$_POST['search'];
        echo '<label for="username" class="col-sm-3 control-label">Status</label>';
        echo '<div class="col-sm-9">';
        echo '<select class="form-control select2" name="status">';
            $cek=$this->db_umum->select("SELECT id,status FROM lembaga where id='$status'");
            foreach($cek as $cek){
                $statusnya = $cek->status;
            }
            $hasil=array(
                "pusat" => "Pusat",
                "cabang" => "Cabang",   
                "unit" => "Unit",
                "proyek" => "Proyek",
                "subproyek" => "Subproyek"
            );
        foreach($hasil as $value => $label)
        {
            $no=0;
            if($value = $statusnya){
                $disable[] = "disabled='disabled'";
            }else{
                $disable[] = "";
            }
            echo "<option value='".$value."' $disable[$no]>".$label."</option>";
            $no++;
        }
        echo '</select></div><br/>'; 
    }

The result is if $value = $statusnya , my whole select2 will disabled. But, It is not what I want. I want only value which is exact with $statusnya is disabled and the other is available. Any advice ?

Answer 1

You are using single equal(=) thats not correct you should use == for compare.

Replace this line

if($value = $statusnya){

with

 if($value == $statusnya){

also define $no outside of foreach

Example:-

$no=0;
foreach($hasil as $value => $label)
{                
    if($value == $statusnya){
        $disable[] = "disabled='disabled'";
    }else{
        $disable[] = "";
    }
    echo "<option value='".$value."' $disable[$no]>".$label."</option>";
    $no++;
}