PHP foreach with counter和IF语句

Question

I am trying to use a FOREACH loop in PHP to output different messages depending on the position of the value in the array. My code is below:

$qtyValidFiles = count($validFiles);
$tick = 0;
                 foreach($validFiles AS $validItem)
                {
                    if($tick = 0)
                    {
                    echo"'#$validItem,";
                    }
                    elseif($tick < $qtyValidFiles -1 && $tick != 0)
                    {
                    echo"#$validItem,";
                    }
                    elseif($tick = $qtyValidFiles -1)
                    {
                    echo"#$validItem'";
                    }
                }; $tick++;

In this instance, $qtyValidFiles has 4 values.

The code above returns:

#Games'#Movies'#Music'#TV' 

which suggests to me that $tick is always being seen as value 3.

Answer 1

If $validFiles is an indexed array, you can do:

foreach ($validFiles as $tick => $validItem)

instead of incrementing $tick yourself.

Your entire loop is unnecessary, though. You can do:

echo "'" . implode(",", array_map(function($x) { return "#$x"; }, $validFiles)) . "'";

This should be better than your code because you don't do the right thing if the array has exactly 1 item; you'll print the beginning quote and a comma, but I think you really want the one element surrounded by quotes.