dongwei1855 2017-01-29 04:02
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jQuery自动完成功能根据我的输入词从数据库中提取项目,但结果显示为列表的水平线

The jQuery autocomplete function brings the item from the database based on my typing word but result shows as just horizontal line of list. Attached image is showing how the result looks like.

Result

HTML:

<form class="navbar-seach pull-center">
    <div>
        <input type="text" placeholder="Search Productstyle="width:550px; height:40px;padding-left: 10px;margin-top: 20px;" id="searchBox" onkeyup="if (event.keyCode === 13) {searchResults(this.value); this.value = '';}">
    </div>
</form>

PHP:

include 'searchbox.php';

$switch_id = filter_input(INPUT_POST, 'switch_id', FILTER_SANITIZE_SPECIAL_CHARS);

if (isset($_POST['name_startsWith']))
    $searchWordResults = $_POST['name_startsWith'];
else
    $searchWordResults = null;

switch($switch_id){
    case 1:
        $userObj = new searchBox();
        echo $userObj->autoComplete($searchWordResults);
        break;
}

jQuery:

$("#searchBox").autocomplete({
    source: function(request, response) {
        $.ajax({
            type: "POST",  
            url: "class/searchbox_switch.php",
            dataType: "json",
            data: { name_startsWith: request.term, switch_id: 1 },
            success: function(data) {
                response($.map(data, function(item){
                    return {
                        label: item.label,
                        value: item.value
                    };
                }));
            },
            error: function(response) {
                console.log(response.responseText);
            }
        });
    },
    autoFocus: true,
    minLength: 1,
    select: function( event, ui ) {
        searchResults(ui.item.label);
    }
});

PHP (searchbox.php):

include '../dbConnect.php';

class searchBox {
    public function autoComplete($name_startsWith) {
        $letterSearch = $name_startsWith . "%";
        $connectObj = new db_connect();
        $dbh = $connectObj->connect();

        $stmt = $dbh->prepare("SELECT product_name FROM products WHERE product_name LIKE :start");
        $stnd = array();
        $stmt->bindParam(':start', $letterSearch, PDO::PARAM_STR);
        $stmt->execute();
        $stnd = $stmt->fetchAll(PDO::FETCH_ASSOC);
        $json = json_encode($stnd);
        return $json;
    }

}
  • 写回答

1条回答 默认 最新

  • dtrvzd1171 2017-01-31 06:58
    关注

    OK got it. You are passing wrong key in your result. Your result data key is "product_name" And You are trying to access "label ". Try This solution:

     success: function( data ) {                
              response( $.map( data, function(item) {                    
                 return {
                       label: item.product_name,
                 }
              }));                    
    
     },
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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