dpikoto468637 2017-04-30 11:04
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从select标签获取值时出错 - PHP

I cant get any value when the code is run , please help

HTML Part :

<form method="post">
    <select name="rebuild">
        <?php while($lo = mysqli_fetch_assoc($resultt)) { ?>
            <option value="<?php echo $lo["company_name"]; ?>">
                <?php echo $lo["company_name"]; ?>
            </option>
        <?php } ?>
    </select>       
</form>

PHP Part:

if (isset($_POST['rebuild'])) {
    $re = $_POST['rebuild'];
}
else {      
   $re = " ";
}

echo $re;   
  • 写回答

1条回答 默认 最新

  • douye8500 2017-04-30 11:16
    关注

    Try this

    <form method="post">
    <select name="rebuild">
        <?php while($lo = mysqli_fetch_assoc($resultt)) { ?>
            <option value="<?php echo $lo["company_name"]; ?>">
                <?php echo $lo["company_name"]; ?>
            </option>
        <?php } ?>
    </select>  
    <input type="submit" name="submit">     
    </form>
    

    your PHP part

    if (isset($_POST['submit'])) {
    $re = $_POST['rebuild'];
    echo $re;
    exit();
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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