在switch语句PHP之外分配的变量为空

Question

public function store($feed) 
    {
        switch($feed)
        {
            case 'full':
                $coupons = json_decode(file_get_contents('path-to-json-feed'), true);
                break;
            case 'incremental':
                $coupons = json_decode(file_get_contents('path-to-different-json-feed'), true);
                break;
         }
        var_dump($coupons);die();
        $this->Deal_model->updateAllDeals($coupons);
        echo 'Coupons Updated';     
    }

I am trying to assign a value to $coupons but var_dump($coupons) returns an empty array.

Answer 1

I'd suggest you add a default, in case $feed is something other than full or incremental.

If this is your actual code, I am not sure if there is a file called path-to-json-feed, but it seems like it should be something else, like the actual path to a JSON file/feed.

Replace path-to-json-feed with an actual file, and try with the below code and see what you get.

public function store($feed) 
{
    switch($feed)
    {
        case 'full':
            $coupons = json_decode(file_get_contents('path-to-json-feed'), true);
            break;
        case 'incremental':
            $coupons = json_decode(file_get_contents('path-to-json-feed'), true);
            break;
        default:
            $coupons = json_decode(file_get_contents('path-to-json-feed'), true);
            break;
     }
    var_dump($coupons);
    die(); // DEBUGGING
    $this->Deal_model->updateAllDeals($coupons);
    echo 'Coupons Updated';     
}