dongpi9494 2014-12-22 17:42
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在php函数中使用copy()

As it stands I have my files being displayed in an array, I am trying to create a function to make a copy of the file in the users directory as it stands my function is as follows:

function copyFile($dir, $fileToCopy){
if (is_dir($dir)) {
    if ($dirHandle = opendir($dir)) {
       $files = array_diff(scandir($dir), array('.', '..', '.htaccess'));
       if($files){
           foreach($files as $file){
               if($file === $fileToCopy) {
                  copy($dir."\\".$fileToCopy, $dir."\\");
                  $output = 'Successfully copied file: '.$fileToCopy;
               }
           }
       }
    }
}
return $output;
    }
    if(isset($_POST)){
echo copyFile($_SESSION['UserFolder'], $_POST['fileToCopy']);
}

The output is given when i click the button to copy the file but nothing happens with regards to the file being copied the buttons code is like so:

'<form action="MyFiles.php" method="POST"><input type="hidden" value="'.$file.'" name="fileToCopy"/><input type="submit" value="Copy" name="copyButton"/></form>'

hope I explained well enough would love some feedback

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1条回答 默认 最新

  • dongzhan5943 2014-12-23 04:36
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    The reason it isn't copying is due to you not giving it a new name, so essentially it is just overwriting the same file. Try adding 'copy' after it like so:

    copy($dir."\\".$fileToCopy, $dir."\\".$fileToCopy."copy");
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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