i think you are having a misunderstanding..
if you want to load an external url into the div block
$('#uses_form_div').load("./a.file");
will do it. see the api docs.
Or if you are trying to load the ajax response of the $.ajax call into the div, it should be
$.ajax({
type: 'POST',
url: $(this).attr('action'),
cache: false,
data: $("#uses_form").serializeArray(),
success: function(data)
{
$('#uses_form_div').html(data); // see here
}
});
UPDATED according to comments below:
if the case of an included page to be refreshed. I have two ways to recommend.
make the included file as a separate url and load it initially. so instead of include
you will be loading it via jquery as the page loads by a jquery load call. and when you want to refresh it you can do $('#uses_form_div').load("./a.file");
you can put it as include it self and when you need to update, make an ajx request get the data back. Here you have 2 choice. You can build the dom at server and give html as ajax response and simply $("#uses_form_div").html(data)
or get the response as json
and build your dom at client side and load it via same $("#uses_form_div").html(data)
.