dongtiao2105 2013-04-19 21:29
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正则表达式捕获记录PHP 2

I'm trying to get the result below, but I can not, could someone give me an idea?

My Cod.:

$string ='ZAMM Et a est hac pid pid sit amet, lacus nisi                   ZPPP scelerisque sagittis montes, porttitor ut arcu                 ZAMM tincidunt cursus eu amet nunc ZAMM c ac nunc, et pid pellentesque amet,                   ZSSS m urna scelerisque in vut';

if(preg_match_all("/ZAMM.*/", $string, $matches)) {
    foreach($matches[0] as $match){
      echo $match;
      echo "<br />";
    }
}

Expected result:

1: ZAMM Et a est hac pid pid sit amet, lacus nisi                   ZPPP scelerisque sagittis montes, porttitor ut arcu                 ZAMM tincidunt cursus eu amet nunc ZAMM c ac nunc, et pid pellentesque amet,                   ZSSS m urna scelerisque in vut

2: ZAMM tincidunt cursus eu amet nunc ZAMM c ac nunc, et pid pellentesque amet,                   ZSSS m urna scelerisque in vut

3: ZAMM c ac nunc, et pid pellentesque amet,                   ZSSS m urna scelerisque in vut
  • 写回答

3条回答 默认 最新

  • dongruidian3064 2013-04-19 21:38
    关注
    /ZAMM(.(?!ZAMM))*/
    

    Take all following characters that are not followed by ZAMM. This is called Negative Lookahead.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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