Does anyone know the syntax for this? I have a PHP file that uses argv to turn a parameter into a variable.
If I use:
php /path/to/local/phpfile/myphpfile.php variable
that works perfectly, but to a remote PHP file:
php http://remotehost/myphpfile.php variable
I get back:
"could not open input file: http://remotehost/myphpfile.php"
Fine, so I try with curl:
curl --data "variable" http://remotehost/myphpfile.php
But the variable does not get passed. Is it possible to pass shell script variables to a remote PHP file? Many thanks in advance.
