dongmou1964 2017-04-10 08:56
浏览 166
已采纳

GD PHP旋转图像黑色边框

I try to resize and rotate an image with PHP (GD) but when image rotate, it add a black border on right.

Exemple image (before resize & rotate): Exemple

Exemple image (after resize & rotate): Exemple of black border add

Here is my code :

    $image = $_FILES["file"]["name"];
    $uploadedfile = $_FILES['file']['tmp_name'];

    if ($image) {

        $filename = stripslashes($_FILES['file']['name']);

        $i = strrpos($filename,".");
        $l = strlen($filename) - $i;
        $ext = substr($filename,$i+1,$l);

        $extension = strtolower($ext);

        if (($extension != "jpg") && ($extension != "jpeg") 
            && ($extension != "png") && ($extension != "gif")) {

            echo ' Unknown Image extension ';
            $errors=1;
        }

        else {
            $size=filesize($_FILES['file']['tmp_name']);

            if($extension=="jpg" || $extension=="jpeg" ) {
                $uploadedfile = $_FILES['file']['tmp_name'];
                $src = imagecreatefromjpeg($uploadedfile);
            }
            else if($extension=="png") {
                $uploadedfile = $_FILES['file']['tmp_name'];
                $src = imagecreatefrompng($uploadedfile);
            }
            else  {
                $src = imagecreatefromgif($uploadedfile);
            }

            $max_width = 175;
            $max_height = 100;

            $size=GetImageSize($uploadedfile);

            $width_ratio = ($size[0] / $max_width);
            $height_ratio = ($size[1] / $max_height);

            if($width_ratio >=$height_ratio) 
            {
                $ratio = $width_ratio;
            }
            else
            {
                $ratio = $height_ratio;
            }

            $new_width = ($size[0] / $ratio);
            $new_height = ($size[1] / $ratio);
            $tmp=imagecreatetruecolor($new_width,$new_height);

            if(function_exists("exif_read_data")){
                $exif = @exif_read_data($uploadedfile);

                $rotateImg = imagerotate($src,0,0);

                if(!empty($exif['Orientation'])) {
                    switch($exif['Orientation']) {
                    case 8:
                        $rotateImg = imagerotate($src,90,0);
                        break;
                    case 3:
                        $rotateImg = imagerotate($src,180,0);
                        break;
                    case 6:
                        $rotateImg = imagerotate($src,-90,0);
                        break;
                    } 
                }
            }

            imagecopyresampled($tmp,$rotateImg,0,0,0,0,($new_width-1),($new_height-1),$size[0],$size[1]);

            $filename = sha1(basename( $_FILES['file']['name']));
            $path = dirname(__FILE__)."/../files/pictures/".$filename;

            imagejpeg($tmp,$path,100);

            imagedestroy($src);
            imagedestroy($rotateImg);
            imagedestroy($tmp);


        }
    }

I tried some modification like the answers of this posts : - A border appears when rotating image with gd + php - PHP - Rotate image with GD gives black borders - Why when i rotate the image black borders appear? PHP GD

But nothing work.

Please guys helps me.

Thanks you

  • 写回答

2条回答 默认 最新

  • dongxu4580 2017-04-12 14:49
    关注

    The problem occurs if the EXIF data indicates rotation is necessary, because after the rotation the values of height and width are still treated the same. Since the image has been rotated these values should be switched with one another.

    The rotation needs to be done first, not last, so move the rotation code above all of the ratio calculations (to just after you declare $size). You'll need to keep track of a 90/-90 degree rotation taking place:

    $rotated = false;
    if (!empty($exif['Orientation'])) {
        switch ($exif['Orientation']) {
            case 8:
                $src = imagerotate($src, 90, 0);
                $rotated = true;
                break;
            case 3:
                $src = imagerotate($src, 180, 0);
                break;
            case 6:
                $src = imagerotate($src, -90, 0);
                $rotated = true;
                break;
        }
    }
    

    Now you need to 'flip' the values if the orientation has changed:

    if ($rotated) {
        $width = $size[1];
        $height = $size[0];
    } else {
        $width = $size[0];
        $height = $size[1];
    }
    

    In the rest of your code replace instances of $size[0] with $width and $size[1] with $height to fix the calculations.

    You could also ...($new_width-1),($new_height-1)... to just ...$new_width, $new_height... to make the resized image fit correctly, otherwise there is a 1px black border on the right and bottom of the resulting image.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥15 虚幻5 UE美术毛发渲染
  • ¥15 CVRP 图论 物流运输优化
  • ¥15 Tableau online 嵌入ppt失败
  • ¥100 支付宝网页转账系统不识别账号
  • ¥15 基于单片机的靶位控制系统
  • ¥15 真我手机蓝牙传输进度消息被关闭了,怎么打开?(关键词-消息通知)
  • ¥15 装 pytorch 的时候出了好多问题,遇到这种情况怎么处理?
  • ¥20 IOS游览器某宝手机网页版自动立即购买JavaScript脚本
  • ¥15 手机接入宽带网线,如何释放宽带全部速度
  • ¥30 关于#r语言#的问题:如何对R语言中mfgarch包中构建的garch-midas模型进行样本内长期波动率预测和样本外长期波动率预测